Or, if we consider a rate of improvement: $$\text{Rate} = \frac{248}{1.9575}$$ $$ \text{Rate} = \frac{248}{1.9575} \approx 126.76 \text{ units/hour} $$
The final answer is: $$\frac{248}{1.9575}$$
If "sone" improves by 248 units over this time, we have: $$S + 248 = S_{better}$$
Let (S) be the starting value of "sone," and (t = 1.9575) hours (1 hour, 57 minutes, and 30 seconds converted to just hours).
Or, if we consider a rate of improvement: $$\text{Rate} = \frac{248}{1.9575}$$ $$ \text{Rate} = \frac{248}{1.9575} \approx 126.76 \text{ units/hour} $$
The final answer is: $$\frac{248}{1.9575}$$
If "sone" improves by 248 units over this time, we have: $$S + 248 = S_{better}$$
Let (S) be the starting value of "sone," and (t = 1.9575) hours (1 hour, 57 minutes, and 30 seconds converted to just hours).
